👤

Ce cantitate de Ca(OH)2 va fi neutralizată de 189g de HNO3?

Răspuns :

miu Ca(OH)2= 74g/mol;  miu HNO3=63g/mol
  
1mol.............2mol
Ca(OH)2+2HNO3= Ca(OH)2 +2H2O
74g............2x63g
x.................189g..............................calculeaza X!
74g...............126g
Ca(OH)2 + 2HNO3 ----> Ca(NO3)2 + 2H2O
x=111g.........189g

MCa(OH)2=74g/mol
MHNO3=63g/mol

imi cer scuze de greseala..