[tex]\displaystyle \\
\{13+[25\times 4-(3\times 11+3\times 22)]\times m\}:2=13 \\ \\
\{13+[25\times 4-(3\times 11+3\times 22)]\times m\}=13\times 2 \\ \\
13+[25\times 4-(3\times 11+3\times 22)]\times m=26 \\ \\
~[25\times 4-(3\times 11+3\times 22)]\times m=26-13 \\ \\
~[25\times 4-(3\times 11+3\times 22)]\times m=13 \\ \\
m= \frac{13}{25\times 4-(3\times 11+3\times 22)} \\ \\
m= \frac{13}{25\times 4-(33+66)}= \frac{13}{100-99} =\frac{13}{1}=\boxed{13}[/tex]