👤

descompuneti in factori
a) [tex] x^{2} +5x+6[/tex]
b) [tex] x^{2} -7x+12[/tex]

sa fie notat fiecare pas
Multumesc




Răspuns :

[tex]a)x^2+5x+6=x^2+2x+3x+6=x(x+2)+3(x+2)=\\ =\boxed{(x+2)(x+3)}\\ \\ b)x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=\\ =\boxed{(x-4)(x-3)}[/tex]
a. x²+5x+6=x²+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)
b. x²-7x+12=x²-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)