n1 moli HC≡C-CH=CH2 + 3H2 ⇒ H3C-CH2-CH2-CH3
n2 moli HC≡C-CH=CH2 +H2 ⇒ H2C=CH-CH=CH2
n3 moli HC≡C-CH=CH2 + 2H2 ⇒H2C=CH-CH2-CH3
n4 moli HC≡C-CH=CH2 nereactinat
n final = n1 + n2 + n3 + n4 = 250 moli
n1 = 0,8·250 = 200moli
n2 = 0,08·250 = 20 moli
n3 = 0,1·250 = 25 moli
n4 = 0,02·250 = 5 moli
n vinilacetilena = 250 moli m = 250·52 = 13000g = 13kg
n H2 = 6·250 = 1500 moli m = 3000g = 3 kg
m amestec = 16 kg