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Suma a patru numere impare consecutive este 75. Afla numerele.

Răspuns :

a+a+2+a+4+a+6=75
4a=75-12
4a=63
a=63:4=15.75
b=16.75
c=17.75
d=18.75
[tex]a+a+2+a+4+a+6=75[/tex]
[tex]4a+12=75[/tex]
[tex]4a=75-12[/tex]
[tex]4a=63[/tex]
[tex]a=63:4[/tex]
[tex]\boxed{a=15,75}[/tex]
[tex]\boxed{b=16,75}[/tex]
[tex]\boxed{c=17,75}[/tex]
[tex]\boxed{d=18,75}[/tex]