Răspuns :
Fie abcd numerele naturale de patru cifre
a,b,c,d - cifre; a,b,c,d∈{0,1,2,3,4,5,6,7,8,9};a ≠ 0
a+b+c+d = 9
Analizam ce valoare poate lua a (9 cazuri) apoi ce valoare poate lua b
- a = 1 ⇒ b+c+d =8
b = 0 ⇒ c+d=8 ⇒ cd∈{08,80,17,71,62,26,35,53,44}
abcd ∈ {1008,1080,1017,1071,1062,1026,1035,1053,1044} -9 nr
b = 1⇒c+d=7⇒cd∈{07,70,16,61,25,52,34,43}
abcd∈{1107, 1170, 1116, 1161, 1125, 1152, 1134, 1143} -8 nr
b = 2⇒c+d=6⇒cd∈{06,60,15,51,24,42,33}
abcd∈{1206, 1260, 1251, 1215, 1224, 1242, 1233} -7 nr
b = 3⇒c+d=5⇒cd∈{05,50,41,14,23,32}
abcd∈{1305,1350,1314,1341,1323,1332} -6 nr
b = 4⇒c+d=4⇒cd∈{04,40,13,31,22}⇒abcd∈{1404,1440,1413,1431,1422} -5 nr
b = 5⇒c+d=3⇒ cd∈{03,30,12,21}⇒abcd∈{1503,1530,1512,1521} -4 nr
b = 6 ⇒c+d=2⇒ cd∈{02,20,11}⇒abcd∈{1602,1620,1611} -3 nr
b = 7 ⇒c+d=1⇒ cd∈{01,10}⇒abcd∈{1701,1710} -2 nr
b = 7⇒c+d=0⇒cd=00 ⇒ abcd = 1800 -1 nr
- a = 2 ⇒ b+c+d =7
b = 0 ⇒c+d=7⇒cd∈{07,70,16,61,25,52,34,43}
abcd∈{2007,2070,2016,2061,2025,2052,2034,2043} -8 nr
b = 1⇒c+d=6⇒cd∈{06,60,15,51,24,42,33}
abcd∈{2106, 2160, 2151, 2115, 2124, 2142, 2133} -7 nr
b = 2⇒c+d=5⇒cd∈{05,50,41,14,23,32}
abcd∈{2205, 2250, 2214, 2241, 2223, 2232} -6 nr
b = 3⇒c+d=4⇒cd∈{04,40,13,31,22}⇒abcd∈{2304,2340,2313,2331,2322}
b = 4⇒c+d=3⇒cd∈{03,30,12,21}⇒abcd∈{2403,2430,2412,2421} -4 nr
b = 5⇒c+d=2⇒cd∈{02,20,11}⇒abcd∈{2502,2520,2511} -3 nr
b = 6⇒c+d=1⇒cd∈{01,10}⇒abcd∈{2601,2610} -2 nr
b = 7⇒c+d=0⇒cd=00 ⇒ abcd = 2700 -1 nr
- a = 3 ⇒ b+c+d =6
b = 0 ⇒c+d=6⇒cd∈{06,60,15,51,24,42,33}
abcd∈{3006,3060,3015,3051,3024,3042,3033} -7 nr
b = 1⇒c+d=5⇒cd∈{05,50,41,14,23,32}
abcd∈{3105,3150,3141,3114,3123,3132} -6 nr
b = 2⇒c+d=4⇒cd∈{04,40,13,31,22}⇒abcd∈{3204,3240,3213,3231,3222}
b = 3⇒c+d=3⇒cd∈{03,30,12,21}⇒abcd∈{3303,3330,3312,3321} -4 nr
b = 4⇒c+d=2⇒cd∈{02,20,11}⇒abcd∈{3402,3420,3411} -3 nr
b = 5⇒c+d=1⇒cd∈{01,10}⇒abcd∈{3501,3510} -2 nr
b = 6⇒c+d=0⇒cd=00 ⇒ abcd = 3600 -1 nr
- a = 4 ⇒ b+c+d =5
b = 0⇒c+d=5⇒cd∈{05,50,41,14,23,32}
abcd∈{4005,4050,4014,4041,4023,4032} -6 nr
b = 1⇒c+d=4⇒cd∈{04,40,13,31,22}⇒abcd∈{4104,4140,4113,4131,4122}
b = 2⇒c+d=3⇒cd∈{03,30,12,21}⇒abcd∈{4203,4230,4212,4221} -4 nr
b = 3⇒c+d=2⇒cd∈{02,20,11}⇒abcd∈{4302,4320,4311} -3 nr
b = 4⇒c+d=1⇒cd∈{01,10}⇒abcd∈{4401,4410} -2 nr
b = 5⇒c+d=0⇒cd=00 ⇒ abcd = 4500 -1 nr
- a = 5 ⇒ b+c+d =4
b = 0⇒c+d=4⇒cd∈{04,40,13,31,22}⇒abcd∈{5040,5004,5013,5031,5022}
b = 1⇒c+d=3⇒cd∈{03,30,12,21}⇒abcd∈{5103,5130,5112,5121} -4 nr
b = 2⇒c+d=2⇒cd∈{02,20,11}⇒abcd∈{5202,5220,5211} -3 nr
b = 3⇒c+d=1⇒cd∈{01,10}⇒abcd∈{5301,5310} -2 nr
b = 4⇒c+d=0⇒cd=00 ⇒ abcd = 5400 -1 nr
- a = 6 ⇒ b+c+d =3
b = 0⇒c+d=3⇒cd∈{03,30,12,21}⇒abcd∈{6003,6030,6012,6021} -4 nr
b = 1⇒c+d=2⇒cd∈{02,20,11}⇒abcd∈{6102,6120,6111} -3 nr
b = 2⇒c+d=1⇒cd∈{01,10}⇒abcd∈{6201,6210} -2 nr
b = 3⇒c+d=0⇒cd=00 ⇒ abcd = 6300 -1 nr
- a = 7 ⇒ b+c+d=2
b = 0⇒c+d=2⇒cd∈{02,20,11}⇒abcd∈{7002,7020,7011} -3 nr
b = 1⇒c+d=1⇒cd∈{01,10}⇒abcd∈{7101,7110} -2 nr
b = 2⇒c+d=0⇒cd=00 ⇒ abcd = 7200 -1 nr
- a = 8 ⇒ b+c+d=1
b = 0⇒c+d=1⇒cd∈{01,10}⇒abcd∈{8001,8010} -2 nr
b = 1⇒c+d=0⇒cd=00 ⇒ abcd = 8100 -1 nr
- a = 9 ⇒ b+c+d = 0
b = 0⇒c+d=0⇒cd=00 ⇒ abcd = 9000 -1 nr
45+36+28+21+15+10+6+3+1 = 165 de numere de patru cifre care au suma cifrelor 9 care respecta cerintele problemei
Vă mulțumim că ați vizitat platforma noastră dedicată Matematică. Sperăm că informațiile oferite v-au fost utile. Dacă aveți întrebări sau aveți nevoie de asistență suplimentară, nu ezitați să ne contactați. Așteptăm cu nerăbdare să vă revedem și nu uitați să ne salvați în lista de favorite!