desenul:
trapez dreptunghic ABCD,BC║AD,AD⊥AB,AB⊥BC
AD baza mica = b
BC baza mare =B
BD⊥DC, BC diagonala
ducem DE⊥BC, E∈BC
∡C=60° (ipoteza) ⇒ ∡ABC=90-60=30° ⇒ DC=B/2 (teorema ∡ 30°)
∡BDC=90-60=30° ⇒ EC=DC/2 (teorema ∡ 30°) ⇒ EC=B/4
EC=B-b=B/4
prin urmare avem sistemul:
(B+b)/2=EF
B-b=B/4
B+b=28
B-b=B/4
2B=28+B/4
7B=28 x 4
B=16 cm
b=28-B=28-16
b=12 cm