n:3=a rest 2
n:5=b rest 4
n:7=c rest 6
n=3a+2
n=5b+4
n=7c+6
Adunam la toate 1.
n+1=3a+3=3(a+1) ⇒ (n+1) ∈ M₃
n+1=5b+5=5(b+1) ⇒ (n+1) ∈ M₅
n+1=7c+7=7(c+1) ⇒ (n+1) ∈ M₇
(n+1) ∈ M₃
(n+1) ∈ M₅
(n+1) ∈ M₇
↓
n+1=[3, 5, 7]
[3, 5, 7]=3·5·7=15·7=105
n+1=105
n=104
....................
Sa ai o zi placuta :)
