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(1^2+2^2+3^2)|(14^2-14)

Răspuns :

1^2+2^2+3^2=2+4+9=15 si 14^2-14=196-14=184, deci (1^2+2^2+3^2) NU divide (14^2-14)

(1+4+9)/(196-14)=14/182.... vezi ca se simplifica...de doua ori...si il lasi asa ca fractie ordinara ireductibila