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calculand 2√3-3√12+√12 vei obtine

Răspuns :

[tex]2 \sqrt{3}-3 \sqrt{12} +\sqrt{12} = \\ \\ 2 \sqrt{3} -2 \sqrt{12}= \\ \\ 2\sqrt{3} -4 \sqrt{3} = \\ \\= -2 \sqrt{3} [/tex]

[tex]\sqrt{12}= \sqrt{2 ^{2}*3 }= 2 \sqrt{3} [/tex]