PM = qRT M =4,878·0,082·350/3,5 = 40g/mol
CnH(2n-2) 14n - 2 = 40 ⇒ n = 3 C3H4
C3H4Br2 %Br = 160·100/200 =80% (B)
C : 3·12·100/M = 10 M = 360 ⇒ C = C3H4Br4
n1 moli C3H4 + Br2 ⇒ C3H4Br2
n2 moli C3H4 + 2Br2 ⇒C3H4Br4
n1 = 4/200 = 1/50 moli
n2 = 18/360 = 1/20 moli n1 / n2 = 1/50 ·20/1 = 2/5
nA = n1 + n2= 1/50 + 1/20 = 7/100 moli V = 22,4·7/100 = 15,68 l
200n1 + 360n2 = 110 g 20n1 + 36n2 = 11
n1/n2 = 2/5 n2 = 2,5n1 20n1 + 90n1 = 11 110 n1 = 11
n1 = 0,1 moli n2 = 0,25moli
nBr2 = n1 + 2n2 = 0,6moli md = 0,6·160 = 96 g ms = 96·100/5 = 1920g
