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problema 6.15, multumesc!

Problema 615 Multumesc class=

Răspuns :

F.g. hidrocarbura aromatica saturata-> CnH2n-6=14n-6

14n-6=106==>14n=112=>n=8 -> F.m C8H10 -> etilbenzen

C6H6 + CH2=CH2 ---> C8H10

C8H10 ---> C6H5-CH=CH2 (vinilbenzen)

C6H5-CH=CH2 ----> -[-C6H5-CH-CH2-]-n 

b) MC8H8=104kg...........................104kg polimer
  52kg.................................................52kg

MC8H10=106kg..................................104kg C8H8
x=53kg......................................................52kg

78kg C6H6........................................106kg C8H10
x=39kg...................................................53kg

n=mp/mt*100==>mp=n*mt/100=78*39/100=30,42kg

1kg=1000g
30,42kg=30420g

ro=m/V==>V=m/ro=30420g/0,88g/cm3=34568,1818cm3=34,568L C6H6