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Intr-o solutie, care cntinea 40 g de sare, s-au turnat 200g de apa si astfel concentratia solutiei s-s micsorat cu 10%. Ce cantitate de apa continea solutia initiala si care era concentratia ei?

Răspuns :

Cp1=?
mH2O=?
md1=40g
mH2O'=200g

Cp=md/ms*100=40/240*100=16,666%

Cp=md/md+mH2O*100=>10=40/40+mH2O*100=>400+10mH2O=4000=>10mH2O=3600=>mH2O=360g