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m(sol)=600g
W=30%

m(subNaCl)=?
m(H2O)=?
V(H2O)=?



Răspuns :

c(omega)= mdx100/ms,   unde ms= md+m,apa
30/100= md/600----> md= m,NaCl= 180g

600= 180+ m,apa---> m,apa= 420g

niu= m/M(miu);    niu= 420g/ 18g/mol=........................calculeaza !!