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Se considera expresiile E1(x)=x³+3x²-4x-12 Si E2(x)=x³+2x²-9x-18
a)Descompuneti expresiile in produse de factori ireductibili
b)Aratati ca E1(x)-E2(x)=(x-2)(x+3)


Răspuns :

E1(x) = x²(x+3) - 4(x+3) = (x+3)(x+2)(x-2)
E2(x) = x²(x+2) - 9(x+2) = (x+2)(x-3)(x+3)
E1(x) - E2(x) = (x+2)(x +3)(x - 2- x +3) = (x+2)(x+3)