a=12m
b=12n
m,n∈N
5a+2b=60m+24n
60m+24n=348 ....:4
15m+6n=87
6n=87-15m
n= (87-15m)/6 ∈N
pt m=0,2;4, 6, 2k numaratorul n este impar, nu se imparte la 6, n∉N
deci nu le vom incerca
pt m=1, obtinem n=72:6=12
ptm=3, obtinem n=42:6=7
ptn=5 obtinem n=12:6=2
ptn≥7, obtinem n mai mic decat 0
deci raman doar
(n,m) ∈multimii (1,12) (3;7) (5,2)
deci (a,b)∈multimii (12,144), (36;84);(60;24) care verifica relatia
