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1.Fie a,b∈N a/b=3/8
7a-2b=60 a×b=?
2. ∡x, ∡y- suplementare (180)
m(x)-m(y)=36 de grade
m(x)=?
m(y)=?


Răspuns :

1)a=3×b/8
7x(3×b/8)-2b=60
21×b/8-2b=60
(21×b-2×8×b)=60×8
21×b-16×b=480
5×b=480
b=96
a=(3×96)/8=36

2)x-y=36
x+y=180

x=36+y
inlocuim
36+y+y=180
2y=144
y=72
x=108