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Dezvoltați:
(3y-2) la a 2a=
(2-x+y)la a 2a=
49-x la a 2a=
(x-x+3) la a 3a=
(y-2)la a3a=


Răspuns :

(3y-2)²=(3y-2)(3y-2)=9y²-12y+4
(2-x+y)²=(2-x+y)(2-x+y)=2+2x+x²-2xy+y²
49-x²=(7-x)*(7+x)
(x-x+3) ³= (0+3)³=3³=27
(y-2)³= y³ – 6y² + 12y – 8