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Determinati numarul: "a" din egalitatile:
68-4X[150-3X( a-5 ): 3] : 10= 20


Răspuns :

68-20=4x[150-3x(a-5):3]:10
48x10=4x[150-(a-5)]
480:4=150-(a-5)
120=150-(a-5)
30=a-5
a=35