👤

cate grame si cate molecule reprezinta 6 moli de carbonat de calciu

Răspuns :

1 mol CaCO3............6,022 * 10^23 molecule
6 moli CaCO3....................x molecule
x = 36.132 * 10^23 molecule
n = m/masa molara => m = n*masa molara = 6*100 = 600 g CaCO3