C6H5-CH3 + O2 => C6H5-COOH + H2O
92 g toluen.............122 g acid benzoic
460 kg toluen.................x kg acid benzoic
x = 610 kg acid benzoic
randamentul = m practica/m teoretica * 100
m practica = 610*76/100 = 463.6 kg acid benzoic
92 g toluen.............1 mol oxigen
460 kg toluen.................x kmoli oxigen
x = 5 kmoli oxigen
V oxigen = n oxigen*22,4 = 5*22.4 = 112 m3 oxigen
V aer = 100/20 * V oxigen = 5*112 = 560 m3 aer
