-clorura metalului MCln are miu=42,5g/mol
miu= A,M+35,5n=42,5-->
n=1--->A,M= 7g/mol-.Li(valenta I)
2mol 0,5mol 1mol
-2Li +1/2O2---> Li2o
2x7g......16g..........(2x7+16)g
28g.......m=32g......m=60g
Li2O +2HCl--> 2LiCl + H2O
30g.................2x42,5
60g....................m,sare= calculeaza !!!!!