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Gaseste sumava+b+c stiind ca a+4b+3c=821,3b+2c=497

Răspuns :

a+4b+3c=821;
3b+2c=497;

Din prima egalitate avem : a+b+c + 3b+2c=821;
stim ca 3b+2c=497; -> a+b+c=821-497; a+b+c=324
(a+4b+3c)-(3b+2c)=821-497
a+4b+3c-3b-2c=a+b+c=324