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(2-√3)³=.....va rog ajutatima

Răspuns :

[tex]\it (a-b)^3 = a^3-3a^2b+3ab^2-b^3[/tex]

[tex]\it (2-\sqrt3)^3 = 2^3-3\cdot2^2\sqrt3+3\cdot2\cdot(\sqrt3)^2 -(\sqrt3)^3[/tex]

[tex]\it = 8-12\sqrt3+18-3 \sqrt3 = 26 - 15\sqrt3 .[/tex]