Enuntul problemei arata astfel:
[tex]x,y,z \in N \\ \\
\left \{\begin{array}{c}x+y+z=2011\\y=6*x\\z=x-173\end{array} \right =\ \textgreater \
\\ \\ x+6*x+x+173 = 2001 \ \textless \ =\ \textgreater \ 8x = 2001-173 \\ \\
8x = 2184 \ \textless \ =\ \textgreater \ x= \frac{2184}{8} =\ \textgreater \ x=273 \\
\\ \left \{\begin{array}{c}y=6*x&\\x=273\end{array}\right=\ \textgreater \ y=6*273=\ \textgreater \ y=1638 \\ \\ \\
\left \{\begin{array}{c}z=x-173&\\x=273\end{array}\right=\ \textgreater \ z=273-173=\ \textgreater \ z=100 \\ \\
Verificare: \\ \\
273+1638+100=2011\ \textless \ =\ \textgreater \ 2011=2011 \ (A)[/tex]
Sper sa te ajute
