Notam a,b,c,d, masurile unghiurilor patrulaterului =>
a+b+c+d=360
Deoarece a,b,c,d sunt invers proportionale cu 2,3,4,6 =>
2a=3b=4c=6d=k =>
a=k/2
b=k/3
c=k/4
d=k/6 =>
a+b+c+d=360(=)k/2+k/3+k/4+k/6=360(=)(6k+4k+3k+2k)/12=360(=)15k/12=360(=)5k/4=360(=)k=288 =>
a=144
b=96
c=72
d=48
