[tex]m_{Ca}=160 \ g \\ \boxed{\nu_{CaO}-?} \\ \bold{Rezolvare:} \\ 2Ca+O_2\to2CaO \\ \boxed{\nu=\frac{m}{M}} \\ \frac{\nu_{CaO}}{2 \ moli}=\frac{\nu_{Ca}}{2 \ moli}; \ \ \ \Rightarrow\nu_{Ca_O}=\nu_{Ca} \\ \nu_{Ca}=\frac{m_{Ca}}{M_{Ca}} \\ M_{Ca}=40 \cdot 1=40 \ g/mol \\ \nu_{Ca}=\frac{160 \ g}{40 \ g/mol}=4 \ moli \\ \Rightarrow \boxed{ \bold{\nu_{CaO}=4 \ moli}}[/tex]
