Initial: solutia de HCl : ms = 300g c = 36,5%⇒ md = 109,5g n1 = 3moli
solutia de NaOH : ms = 200g c = 40% ⇒ md = 80g n2 = 2moli
reactioneaza : 2moli HCl + 2moliNaOH ⇒ 2moli NaCl + 2moliH2O
final : ms = 300g + 200g = 500g md1 = 2·58,5 = 117gNaCl
md2 = 36,5gHCl
c1 = 117·100/500 = 23,4% NaCl
c2 = 3650/500 = 7,3%HCl