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Determinati valorile lui x si t astfel incat :3x² +2√3x +5y²+ 2√5y =-2

Răspuns :

(3x² +2√3x +1) + ( 5y²+ 2√5y +1)=0
(3x+1)^2 + (5y+1)^2 =0
√3x+1=0, x=√ -1/3
√5y+1=0, y= √-1/5