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1) Restrangeti ca patrat sumele :
a) [tex]3 x^{2} - 2 \sqrt{3} +1[/tex]
b)[tex]3+2 \sqrt{3} x + x^{2} [/tex]
c) [tex] x^{2} - \frac{2}{3} x + \frac{1}{9} [/tex]


Răspuns :

   
[tex]\displaystyle \\ a)~~ 3x^{2} - 2 \sqrt{3}x +1 = (x\sqrt{3})^2 + 2\times (x\sqrt{3})\times (-1)^2=(x\sqrt{3} -1)^2 \\ \\ \\ b)~~3+2 \sqrt{3} x + x^{2} =(\sqrt{3})^2 + 2\times \sqrt{3} \times x + x^2=(\sqrt{3}+x)^2 \\ \\ \\ c)~~x^{2} - \frac{2}{3} x + \frac{1}{9} = x^{2} + 2\times x \times \Big(-\frac{1}{3}\Big) + \Big(\frac{1}{3}\Big)^2 =\Big(x-\frac{1}{3}\Big)^2[/tex]