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Calculeaza masa de amoniac obtinuta prin descompunere a 5 moli de carbonat de amoniu

Răspuns :

(NH4)2CO3 => 2NH3 + CO2 + H2O

M(NH4)2CO3 = 2(AN+4AH)+AC+3AO = 2(14+4*1)+12+3*16=96g/mol

MNH3=AN+3AH=14+3*1=17g/mol

1 mol (NH4)2CO3........................2*17g NH3
5 moli (NH4)2CO3........................xg NH3

x=2*17*5= Calculeaza !!