n=2k+1
n=3l+1
n=4m+1
n=5p+1
n=6r+1
n=7q
n-1=2k
n-1=3l+
n-1=4m
n-1=5p
n-1=6r
(n-1)minim = c.m/m/m.c[2,3,4,5,6]=60
n minim=61
n e de forma =60s+1, s∈ N
e necesar ca
7|60s+1
n ∈{ 61,121,181,241,301,...}
7|301
Verificare
301:7=43
301 im[partite pe rand la 2,3,4,5,6 da de fiecare data rest1
Problema e corect rezolvata
raspuns 301 piese
