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Calculati volumul co2 care se degaja la arderea a 100 g pentan

Răspuns :

MC5H12=72g/mol

n=m/M=100/72=1,3(8) moli C5H12

C5H12 + 6O2 => 5CO2 + 6H2O + Q

1 mol C5H12.....................5*22,4 L CO2
1,3(8) moli C5H12...............x L CO2

x=5*22,4*1,3(8) =