- calculez masa de clorura dizolvata
c/100= md/ms
5,2/100= md/200----> md=10,4gBaCl2
M,BaCl2= (137gBa+2x35,5gCl)/mol= 208g/mol
M,H2SO4= (2gH+32gS+4X16gO)/mol= 98g/mol
- ecuatia reactiei
1mol 1mol
BaCl2 + H2SO4-----> BaSO4 + 2HCl
208g..........98g
10,4g..........x
x= 10,4x98/208= calculeaza !!!!