a) 1 mol Ag....................6,023*10^23 atomi
0,5 moli Ag.....................x=6,023*0,5*10^23 atomi Ag
b) 0,5 kmoli =500 moli Ag
1 mol Ag..................6,023*10^23 atomi
500 moli Ag..............x=6,023*500*10^23 atomi
c) 12g C........................6,023*10^23 atomi
100g C..........................x=6,023*100/12*10^23 atomi
d) n=m/M=120/12=10 kmoli C
12kmoli =10000 moli C
1 mol C...................6,023*10^23 atomi
10000 moli C...........x=6,023*10^27 atomi