alcool : CxH(2x+2)Oy ⇔ CxH(2x+2-y)(OH)y M A = 14x + 16y +2 = 92 14x+16y = 90 7x + 8y = 45
1mol A + y moli anhidrida ⇒ CxH(2x+2-y)(OCOCH3)y + yCH3COOH
compus final : M = 14x+2-y+ 59y = 14x +58y + 2 = 218 14x +58y = 216
7x + 29y = 108 21y = 63 y = 3 x = 3
A : C3H8O3 = glicerina