[tex]36^{log_65}+10^{1-lg2}-3^{log_936}= \\ \\
= (6^2)^{log_65}+10^{lg10-lg2}-3^{log_{3^2}36} \\ \\
= 6^{2log_65}+10^{lg \frac{10}{2} }-3^{ \frac{1}{2} log_{3}36} \\ \\
= 6^{log_65^2}+10^{lg 5 }-3^{ log_{3}36^\frac{1}{2} } \\ \\
= 6^{log_625}+5-3^{ log_{3} \sqrt{36} } \\ \\
= 25+5-3^{ log_{3} 6 } \\ \\
= 25+5-6 \\ \\
= 24[/tex]
