n=8k+7
n=12l+11
n=15m+14
n+1=8k+7+1
n+1=12l+11+1
n+1=15m+14+1
n+1=8k+8
n+1=12l+12
n+1=15m+15
n+1=8s
n+1=12p
n+1=15r
(n+1) minim=c.m.m.m.c(8,12,15)=c.m.m.m.c(2³,2² *3, 3*5)=
2³ *3 *5=8*3*5=120
n minim =120-1=119. cerinta
Obs. artificiul cu adunarea unui anume numar este posibil doar daca de fiecare data diferenta intre cat si rest este aceeasi .
In acest caz:8-7=12-11=15-14=1
