ECUATIA REACTIEI
2mol 1mol 1mol 2mol
2NaOH + H2SO4---> Na2SO4 + 2H2O
2x40g...........98g.............142g...............2x18g
2g.............x=2,45g.........y=3,55g.........z=0,9g
-md=2,45g ms=50g
c/100=md/ms----> c= 2,45x100/50......................calculeaza !!
ms=md+m,apa---> m,apa= 50-2,45=> 47,55g
m,sare=3,55g =md in solutia finala
ms=md+ m,apa din reactie + m,apa din sol acid= 3,55+47,55+0,9=52g
conc. sarii: c/100= 3,55/52-------------------> calculeaza !!!