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comparati puterile: 3 43 9 21

Răspuns :

[tex] 9^{21}=(3^2)^{21}=3^{2*21}=3^{42} ----->3^{43}>3^{42}----->3^{43}>9^{21} [/tex]
[tex] 9^{21}=( 3^{2} )^{21} =3^{2*21}= 3^{42} \\ \\ 3^{43} \ \textgreater \ 3^{42} \\ \\ [/tex]

deci [tex]9^{21}\ \textless \ 3 ^{43} [/tex]