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(3la52-3la51-3la50)totul la puterea2

Răspuns :

[tex] (3^{52}-3^{51}-3^{50})^2=[3^{50}(3^2-3-1)]^2=(3^{50}*5)^2=3^{100}*25 [/tex]
(3⁵² - 3⁵¹ - 3⁵⁰)² =
[3⁵⁰(3² - 3¹ - 3⁰)]² = 
[3⁵⁰(9 - 3 - 1)]² = 
(3⁵⁰ * 5)² = 
3¹⁰⁰ * 5²