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(m-2)x^2+(3m-5)x+3=0 x1=x2

Răspuns :

x₁=x₂    Δ=b²-4ac=0
a=m-2
b=3m-5
c=2
(3m-5)²-4(m-2)×3=0
9m²-30m+25-12m+24=0
9m²-42m+49=0
(3m-7)²=0
3m-7=0
m=7/3

a=7/3-2=(7-6)/3=1/3
b=3×7/3-5=2
x₁=x₂=-b/2a=-2/(2×1/3)=-3