M(miu)=(64gCu+12gC+3x16g)/mol=124g/mol CuCO3
M= (64gCu+2x35,5gCl)/mol=135g/mol CuCl2
M= (1gH+35,5gCL)/mol= 36,5g/mol HCl
ecuatia reactiei este
1mol.........2mol........1mol
CuCo3 +2HCl----->CuCl2 +CO2+H2O
124g.........2x36,5.......135g
78g..................x..........y
x=78x2x36,5/124=.............gHCl.....calculeaza !!!
y= 78x135/124=.................gCuCl2....calculeaza !!!!