Răspuns:
[tex]\displaystyle \frac{1}{5};\frac{1}{2};1;\frac{1}{2};\frac{1}{5};\frac{1}{10}[/tex]
Explicație pas cu pas:
Functia noastra are forma:
[tex]\displaystyle f(x)=\frac{1}{x^2+1}[/tex]
|nlocuim fiecare numar in functie si avem:
[tex]\displaystyle f(-2)=\frac{1}{(-2)^{2}+1}=\frac{1}{4+1}=\frac{1}{5}[/tex]
[tex]\displaystyle f(-1)=\frac{1}{(-1)^{2}+1}=\frac{1}{1+1}=\frac{1}{2}[/tex]
[tex]\displaystyle f(0)=\frac{1}{(0)^{2}+1}=\frac{1}{1}=1[/tex]
[tex]\displaystyle f(1)=\frac{1}{(1)^{2}+1}=\frac{1}{2}[/tex]
[tex]\displaystyle f(2)=\frac{1}{(2)^{2}+1}=\frac{1}{4+1}=\frac{1}{5}[/tex]
[tex]\displaystyle f(3)=\frac{1}{(3)^{2}+1}=\frac{1}{9+1}=\frac{1}{10}[/tex]
