1mol 2mol 1mol 1mol
Zn + 2HCl----> ZnCl2 + H2
x........y.............3mol
x= 3molZn
m= n x A; m= 3molx65g/mol=........................calculeaza!!
y=6molHCl
m=n x M(miu); m= 6molx36,5g/mol=......................calculeaza : aceasta valoare reprezinta masa dizolvata in solutia dat ,care are,cred, o concentratue procentuala c%
c/100= md/ms
c/100= 6x36,5/ ms------------------------> calculezi ms !!!!