Zn + 2HCl => ZnCl2 + H2
65g Zn...............2*36,5g HCl..............136g ZnCl2............2g H2
xg.........................100g..........................y..............................z
x=65*100/73=Calculeaza !!
y=136*100/73=186,3g ZnCl2
z=2*100/73=2,739g H2
n=m/M=186,3/136=Calculeaza ! (moli)
n=m/M=2,739/2= Calculeaza ! (moli)