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Ce concentratie procentuala are solutia obtinuta prin amestecarea a 400g saramura de c=40% cu 1,2 kg apa

Răspuns :

C=md/ms*100=>md=C*ms/100=40*400/100=160g 

mH2O=1,2kg=1200g 

ms final = 400+1200=1600g sol.

Cfinal = md/msf*100 = 160/1600*100 = Calculeaza !!