A,Zn= 65g/mol; M(miu)=(1gH+35,5gCl)/mol= 36,5g/mol
65g 73g
Zn + 2HCl-----> ZnCl2 +H2
6,5g.. .m=7,3g
ce masa de solutie si ce volum contine aceasta masa de acid ?
c/100= md/ms
22/100= 7,3/ms---> ms=33,18g solutie
d=m/V---> V=m/d---> V= 33,18g/1,18g/ml=..................calculeaza !!!