m oli H2= 224l/22,4l/mol= 10molH2
1mol,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,1mol
Zn + 2HCl---> ZnCl2 + H2 ori a
2mol.................................3mol
2Al +6HCl ---->2AlCl3 + 3H2 ori a
1mol.................................1,5mol
total moli H2= a+1,5a---->10----> a=4mol
mZn= 4molx65g/mol=260g
m,Al= 4molx27g/mol=108g
mZn+mAl= 368g
368g......................260gZn......................108gAl
100g...........................x................................y------------calculeaza x,y !!!
