A,Na= 23g/mol; M,NaOH=(23gNa+16gO+1gH)/mol= 40g/mol
ecuatia reactiei este:
2mol............................2mol
2Na+ 2H2O----> 2NaOH + H2
2x23g........................2x40g
4,6g............................m=8gNaOH
TEORETIC TREBUIE SA SE OBTINA 8gNaOH.....PRACTIC SE OBTINE MAI PUTIN-6g
eta=m,prx100/m,teor; eta= 6x100/8=..................calculeaza !!!!